1、创建varry

CREATE OR REPLACE TYPE Varchar2Varray IS VARRAY(100) of VARCHAR2(40);

2、创建分割函数

CREATE OR REPLACE FUNCTION f_strsplit (STRING VARCHAR2, substring VARCHAR2)
   RETURN varchar2varray
IS
   len       INTEGER        := LENGTH (substring);
   lastpos   INTEGER        := 1 - len;
   pos       INTEGER;
   num       INTEGER;
   i         INTEGER        := 1;
   ret       varchar2varray := varchar2varray (NULL);
   v_str     VARCHAR2 (20);
 /**自定义split函数,将指定的字符串按指定的标志符分割成字符数组*/
BEGIN
   LOOP
      pos := INSTR (STRING, substring, lastpos + len);

      IF pos > 0
      THEN                                                            --found
         num := pos - (lastpos + len);
      ELSE                                                         --not found
         num := LENGTH (STRING) + 1 - (lastpos + len);
      END IF;

      IF i > ret.LAST
      THEN
         ret.EXTEND;
      END IF;

      v_str := SUBSTR (STRING, lastpos + len, num);
      --DBMS_OUTPUT.put_line (v_str);

      ret(i) := v_str;

      EXIT WHEN pos = 0;
      lastpos := pos;
      i := i + 1;
   END LOOP;

   RETURN ret;
END;

3、调用

select * from tab_dailyreport_user where user_id in (
  SELECT * FROM 
( TABLE( select f_strsplit(user_invite,',')
                        from tab_dailyreport_user t
                       where t.user_id = 168148)));

说明：主要是改写开发提过来的一个sql语句的帮助

select * from tab_dailyreport_user where user_id in (
--'166445','164216','171128','184427','160113','160133','160134','160138','160144','160163','160587','166457','167914','168076','168192','168997','169842','169901','184407','184747','185089','185130','208134','208141','208143','208183','160142','166455','167838','168074','168194','168666','185088','185138','185145','208103','169844','171071','160107','166421','166874','168193','179871','179872','184096','184228','184232','184269','184774','184969','185111','207871','160167','161813','14880','134','164355','168149')
select substr(regexp_replace,3,length(regexp_replace)-4) from (
select regexp_replace((select user_invite
                        from tab_dailyreport_user t
                       where t.user_id = 168148),
                      '(,)',
                      chr(39)||','||chr(39)) regexp_replace
  from dual) )

括号里面的语句查询出来的结果是注释部分，直接使用注释的部分在in中可以查询，如果使用里面的语句不能查询，他们的需求是想把外面的user_id在里面的语句中的，可是oracle会把里面的in查询出来的结果作为一个整体，从而出现number类型不能和varchar类型匹配的提示，采用方法是分割in里面查询出来的语句，然后类型转换为table进行查询。