Process OS id : xxxxx alive after kill

Process OS id : xxxxx alive after kill警告

Mon May 21 04:55:06 2012
Shutting down instance (immediate)
License high water mark = 373
Mon May 21 04:55:06 2012
Stopping Job queue slave processes
Mon May 21 04:55:06 2012
Job queue slave processes stopped
All dispatchers and shared servers shutdown
Mon May 21 04:55:14 2012
Process OS id : 9922 alive after kill
Errors in file 
Mon May 21 04:55:16 2012
Process OS id : 8159 alive after kill
Errors in file /oracle/admin/resultdb/udump/resultdb_ora_14639.trc
Mon May 21 04:55:17 2012
Process OS id : 8285 alive after kill
Errors in file /oracle/admin/resultdb/udump/resultdb_ora_14639.trc
Mon May 21 04:55:33 2012
ALTER DATABASE CLOSE NORMAL

错误原因

On some platforms it takes some time to kill processes--AIX being one of those platforms

There have been previous reports of shutdown taking time on AIX and after all Oracle waits were taken out of
the picture it was determined to be due to the way the kill command is implemented on that platform. 


Bug 4931101 ERRORS IN ALERT LOG DURING SHUTDOWN

处理建议

Ignore the error  as all processes will be closed and shutdown will complete successfully.

补充说明
本次出问题的数据库是运行在 linux 平台上的 10.2.0.3

主键表插入数据不提交,外键表插入数据被阻塞

有客户和我说:他在含主外键的表中实验发现,在主表数据未提交,然后在外键表插入该数据数据时,出现外键表hang住现象.我开始以为是不同的会话,根据oracle数据库的一致性原则,应该新会话在外键表中不能知道这个记录的存在,直接报错.
可是我实验结果证明:外键表会被阻塞.分析原因如下:
模拟环境

SQL> create table t_p(id number primary key,name varchar2(100));

Table created.

SQL> create table t_f(fid number primary key,pid number, foreign key(pid) references  t_p(id));

Table created.

--会话1
SQL> insert into t_p values(1,'xifenfei');

1 row created.

SQL> commit;

Commit complete.

--会话2
SQL> insert into t_f values(1,1);

1 row created.

SQL> commit;

--会话1
SQL> insert into t_p values(2,'XIFENFEI');

1 row created.

--会话2
SQL> insert into t_f values(2,2);
--hang住

通过实验发现,当主键数据没有提交,然后在外键表中插入该数据外键数据时,该条记录会处于hang住状态(等待),那是什么原因导致了这个等待呢?对会话2做一个10046的trace,发现如下

*** 2012-05-17 17:25:41.757
WAIT #3065187488: nam='enq: TX - row lock contention' ela= 27002895 name|mode=1415053316 usn<<16 
| slot=262151 sequence=588 obj#=-1 tim=1337246741756917
EXEC #3065187488:c=4000,e=27004456,p=0,cr=2,cu=14,mis=0,r=0,dep=0,og=1,
plh=0,tim=1337246741757690
ERROR #3065187488:err=1013 tim=1337246741757751
STAT #3065187488 id=1 cnt=0 pid=0 pos=1 obj=0 op='LOAD TABLE CONVENTIONAL  
(cr=0 pr=0 pw=0 time=12 us)'
WAIT #3065187488: nam='SQL*Net break/reset to client' ela= 581 driver 
id=1650815232 break?=0 p3=0 obj#=-1 tim=1337246741782587
WAIT #3065187488: nam='SQL*Net message to client' ela= 2 driver id=1650815232 
#bytes=1 p3=0 obj#=-1 tim=1337246741782668

通过这个trace发现,是因为TX锁导致了外键表上的插入操作被阻塞.出现该问题的原因
有两种可能:1.两次插入(主键表和外键表分别插入)在主键表上有不兼容锁;2.外键表上有不兼容性锁.

使用oradebug跟踪会话

oradebug setmypid
--EVENT 10704跟踪锁的使用情况
oradebug EVENT 10704 trace name context forever,level 10
--插入数据操作
oradebug EVENT 10704 trace name context off
oradebug TRACEFILE_NAME

跟踪主键表插入数据

*** 2012-05-17 19:05:52.410
ksqgtl *** TM-00012892-00000000 mode=3 flags=0x401 timeout=21474836 ***
ksqgtl: xcb=0x343c0e54, ktcdix=2147483647, topxcb=0x343c0e54
        ktcipt(topxcb)=0x0

*** 2012-05-17 19:05:52.411
ksucti: init txn DID from session DID 
ksqgtl:
        ksqlkdid: 0001-0013-0000000F

*** 2012-05-17 19:05:52.429
*** ksudidTrace: ksqgtl
        ktcmydid(): 0001-0013-0000000F
        ksusesdi:   0000-0000-00000000
        ksusetxn:   0001-0013-0000000F
ksqgtl: RETURNS 0

*** 2012-05-17 19:05:52.430
ksqgtl *** TM-00012894-00000000 mode=3 flags=0x401 timeout=21474836 ***
ksqgtl: xcb=0x343c0e54, ktcdix=2147483647, topxcb=0x343c0e54
        ktcipt(topxcb)=0x0

*** 2012-05-17 19:05:52.430
ksucti: init session DID from txn DID: 
ksqgtl:
        ksqlkdid: 0001-0013-0000000F

*** 2012-05-17 19:05:52.430
*** ksudidTrace: ksqgtl
        ktcmydid(): 0001-0013-0000000F
        ksusesdi:   0000-0000-00000000
        ksusetxn:   0001-0013-0000000F
ksqgtl: RETURNS 0

*** 2012-05-17 19:05:52.431
ksqgtl *** TX-00050019-00000307 mode=6 flags=0x401 timeout=0 ***
ksqgtl: xcb=0x343c0e54, ktcdix=2147483647, topxcb=0x343c0e54
        ktcipt(topxcb)=0x0

*** 2012-05-17 19:05:52.431
ksucti: init session DID from txn DID: 
ksqgtl:
        ksqlkdid: 0001-0013-0000000F

*** 2012-05-17 19:05:52.431
*** ksudidTrace: ksqgtl
        ktcmydid(): 0001-0013-0000000F
        ksusesdi:   0000-0000-00000000
        ksusetxn:   0001-0013-0000000F
ksqgtl: RETURNS 0



SQL> SELECT TO_NUMBER(12892,'xxxxxxx') from dual;

TO_NUMBER(12892,'XXXXXXX')
--------------------------
                     75922

SQL> SELECT TO_NUMBER(12894,'xxxxxxx') from dual;

TO_NUMBER(12894,'XXXXXXX')
--------------------------
                     75924

SQL> select object_name from dba_objects where object_id in(75922,75924);

OBJECT_NAM
----------
T_P
T_F

通过锁使用情况跟踪可以知道,在主键表插入一条记录时,先在主键表获得TM锁,然后外键表获得TM锁,最后主键表获得TX MODE=6的锁。

跟踪外键表插入数据

*** 2012-05-17 19:49:24.912
ksqgtl *** TM-00012892-00000000 mode=3 flags=0x401 timeout=21474836 ***
ksqgtl: xcb=0x343a45e8, ktcdix=2147483647, topxcb=0x343a45e8
        ktcipt(topxcb)=0x0

*** 2012-05-17 19:49:24.912
ksucti: init txn DID from session DID 
ksqgtl:
        ksqlkdid: 0001-0015-00000064

*** 2012-05-17 19:49:24.913
*** ksudidTrace: ksqgtl
        ktcmydid(): 0001-0015-00000064
        ksusesdi:   0000-0000-00000000
        ksusetxn:   0001-0015-00000064
ksqgtl: RETURNS 0

*** 2012-05-17 19:49:24.913
ksqgtl *** TM-00012894-00000000 mode=3 flags=0x401 timeout=21474836 ***
ksqgtl: xcb=0x343a45e8, ktcdix=2147483647, topxcb=0x343a45e8
        ktcipt(topxcb)=0x0

*** 2012-05-17 19:49:24.913
ksucti: init session DID from txn DID: 
ksqgtl:
        ksqlkdid: 0001-0015-00000064

*** 2012-05-17 19:49:24.913
*** ksudidTrace: ksqgtl
        ktcmydid(): 0001-0015-00000064
        ksusesdi:   0000-0000-00000000
        ksusetxn:   0001-0015-00000064
ksqgtl: RETURNS 0

*** 2012-05-17 19:49:24.913
ksqgtl *** TX-0002001f-0000034a mode=6 flags=0x401 timeout=0 ***
ksqgtl: xcb=0x343a45e8, ktcdix=2147483647, topxcb=0x343a45e8
        ktcipt(topxcb)=0x0

*** 2012-05-17 19:49:24.913
ksucti: init session DID from txn DID: 
ksqgtl:
        ksqlkdid: 0001-0015-00000064

*** 2012-05-17 19:49:24.914
*** ksudidTrace: ksqgtl
        ktcmydid(): 0001-0015-00000064
        ksusesdi:   0000-0000-00000000
        ksusetxn:   0001-0015-00000064
ksqgtl: RETURNS 0

*** 2012-05-17 19:49:24.914
ksqgtl *** TX-00050019-00000307 mode=4 flags=0x10021 timeout=21474836 ***
ksqgtl: xcb=0x343a45e8, ktcdix=2147483647, topxcb=0x343a45e8
        ktcipt(topxcb)=0x0

*** 2012-05-17 19:49:24.914
ksucti: init session DID from txn DID: 
ksqgtl:
        ksqlkdid: 0001-0015-00000064

*** 2012-05-17 19:49:24.914
*** ksudidTrace: ksqgtl
        ktcmydid(): 0001-0015-00000064
        ksusesdi:   0000-0000-00000000
        ksusetxn:   0001-0015-00000064

*** 2012-05-17 19:49:24.914
ksqcmi: TX,50019,307 mode=4 timeout=21474836

从这里可以发现:先在主键表和外键表上加上TM锁,然后外键表获得TX MODE=6的锁(这边成功,因为该表上未有其他级别不兼容锁),再需要在主键表上获得TX MODE=4(表结构共享锁+所有记录共享锁),但是这个时候,发现该锁上已经在主键表插入数据未提交的时候,已经含有了TX MODE=6的锁,从而使得TX MODE=4无法获得,从而使得外键表插入数据处于阻塞状态.

rac redo log file被意外覆盖数据库恢复

当前日志被覆盖导致错误
朋友的一客户在一套rac上包含了两个数据库,其其中一个库增加redo group时候,覆盖了另外一个库的redo,悲剧的是刚好是current redo

Wed May 16 17:03:05 2012
ALTER DATABASE OPEN
This instance was first to open
Wed May 16 17:03:09 2012
Beginning crash recovery of 2 threads
 parallel recovery started with 15 processes
Wed May 16 17:03:11 2012
Started redo scan
Wed May 16 17:03:11 2012
Errors in file /oracle/admin/odsdb/udump/odsdb1_ora_2040024.trc:
ORA-00305: log 14 of thread 1 inconsistent; belongs to another database
ORA-00312: online log 14 thread 1: '/dev/rods_redo1_2_2'
ORA-00305: log 14 of thread 1 inconsistent; belongs to another database
ORA-00312: online log 14 thread 1: '/dev/rods_redo1_2_1'
Abort recovery for domain 0
Wed May 16 17:03:11 2012
Aborting crash recovery due to error 305
Wed May 16 17:03:11 2012
Errors in file /oracle/admin/odsdb/udump/odsdb1_ora_2040024.trc:
ORA-00305: log 14 of thread 1 inconsistent; belongs to another database
ORA-00312: online log 14 thread 1: '/dev/rods_redo1_2_2'
ORA-00305: log 14 of thread 1 inconsistent; belongs to another database
ORA-00312: online log 14 thread 1: '/dev/rods_redo1_2_1'
ORA-305 signalled during: ALTER DATABASE OPEN...
Wed May 16 17:03:13 2012
Shutting down instance (abort)

使用_allow_resetlogs_corruption= TRUE进行恢复

Wed May 16 18:16:48 2012
SMON: enabling cache recovery
Wed May 16 18:16:48 2012
Instance recovery: looking for dead threads
Instance recovery: lock domain invalid but no dead threads
Wed May 16 18:16:48 2012
Errors in file /oracle/admin/odsdb/udump/odsdb1_ora_2105454.trc:
ORA-00600: internal error code, arguments: [kclchkblk_4], [2522], [18446744072024280773], 
[2522], [18446744072024247666], [], [], []
Wed May 16 18:16:50 2012
Errors in file /oracle/admin/odsdb/udump/odsdb1_ora_2105454.trc:
ORA-00600: internal error code, arguments: [kclchkblk_4], [2522], [18446744072024280773], 
[2522], [18446744072024247666], [], [], []
Wed May 16 18:16:50 2012
Error 600 happened during db open, shutting down database
USER: terminating instance due to error 600
Instance terminated by USER, pid = 2105454
ORA-1092 signalled during: alter database open resetlogs...

ORA-600[KCLCHKBLK_4], is signaled because the SCN in a tempfile block is too high.
The same reason caused the ORA-600[2662]s in the alert logs.
因为是临时文件的scn太大的问题,那就比较好解决:
启动数据库到mount状态,查询出来相关temp file,然后drop掉.

ORA-00600[6856]

Wed May 16 20:25:16 2012
Errors in file /oracle/admin/odsdb/bdump/odsdb1_smon_2482210.trc:
ORA-00339: archived log does not contain any redo
ORA-00334: archived log: '/dev/rods_redo2_1_1'
ORA-00600: internal error code, arguments: [6856], [0], [0], [], [], [], [], []
ORACLE Instance odsdb1 (pid = 16) - Error 600 encountered while recovering transaction 
(10, 8) on object 7162533.
Wed May 16 20:25:16 2012
Errors in file /oracle/admin/odsdb/bdump/odsdb1_smon_2482210.trc:
ORA-00600: internal error code, arguments: [6856], [0], [0], [], [], [], [], []

这里的4193和4194是比较熟悉的,根据这里的提示猜测6856也是和undo有关系
ORA-600[6856]SMON is trying to recover a dead transaction.
But the undo application runs into an internal error (trying to delete a row that is already deleted).
因为smon回滚的时候出现上面错误,解决方法是想办法终止回滚,使用event=”10513 trace name context forever, level 2″.

ORA-00600[4193]/ORA-00600[4194]

Wed May 16 20:25:17 2012
Errors in file /oracle/admin/odsdb/udump/odsdb1_ora_2547936.trc:
ORA-00339: archived log does not contain any redo
ORA-00334: archived log: '/dev/rods_redo2_1_1'
ORA-00600: internal error code, arguments: [4194], [22], [25], [], [], [], [], []
Wed May 16 20:25:18 2012
Errors in file /oracle/admin/odsdb/udump/odsdb1_ora_2547936.trc:
ORA-00339: archived log does not contain any redo
ORA-00334: archived log: '/dev/rods_redo2_1_1'
ORA-00600: internal error code, arguments: [4194], [22], [25], [], [], [], [], []
Wed May 16 20:25:56 2012
Errors in file /oracle/admin/odsdb/udump/odsdb1_ora_2547936.trc:
ORA-00600: internal error code, arguments: [4193], [22248], [22252], [], [], [], [], []

太常见错误,不再做说明,虽然使用event是的库open成功,因为部分回滚段有问题,该错误还是会出现(还是喜欢直接屏蔽回滚段)

ORA-00600[ktpridestroy2]

Wed May 16 20:36:26 2012
Errors in file /oracle/admin/odsdb/bdump/odsdb1_smon_2101296.trc:
ORA-00600: internal error code, arguments: [ktpridestroy2], [], [], [], [], [], [], []

This error could be the result of a corruption and involves the parallel rollback that SMON enables each startup.
解决:fast_start_parallel_rollback=false

ORA-00600[kturacf1]/ORA-00600[kcbgcur_9]

Wed May 16 20:49:15 2012
Errors in file /oracle/admin/odsdb/bdump/odsdb1_j000_2007088.trc:
ORA-00600: internal error code, arguments: [kturacf1], [2097152], [], [], [], [], [], []
ORA-00600: internal error code, arguments: [kcbgcur_9], [780140563], [4], [4294959056], [2097152], [], [], []

ORA-00600[kturacf1]错误未查询到原因
ORA-00600[kcbgcur_9]错误原因可能是:Buffers are pinned in a specific class order to prevent internal deadlocks.
因为这两个错误是job产生非致命错误,在这次的处理过程中可以忽略

ORA-00600[4097]

Wed May 16 21:05:05 2012
Errors in file /oracle/admin/odsdb/bdump/odsdb1_j000_1716282.trc:
ORA-12012: error on auto execute of job 6603
ORA-20001: ORA-00600: internal error code, arguments: [4097], [], [], [], [], [], [], []
ORA-06512: at "EPBI.UP_SYSLOG_ONLINE_USER", line 141
ORA-00600: internal error code, arguments: [4097], [], [], [], [], [], [], []

When an instance has a rollback segment offline and the instance crashes, or
the user does a shutdown abort, the rollback segment wrap number does not get
updated. If that segment is then dropped and recreated immediately after the
instance is restarted, the wrap number could be lower than existing wrap
numbers. This will cause the ORA-600[4097] to occur in subsequent
transactions using Rollback.
这个错误也是因为回滚段wrap number未被及时更新导致的异常.

总结这次恢复过程
1.因当前redo丢失,使用隐含参数打开库,然后出现ORA-600[KCLCHKBLK_4](这个错误比较少见,更何况这个库是10.2.0.4)
2.undo出现问题出现ORA-00600[6856]错误不是很多见
3.接下来都是一些列undo导致的问题,其实如果开始就直接使用隐含参数删除掉有问题回滚段,效果可能会比event好.
4.因为部分trace文件没有拿到,未做深入分析,文章列出整体恢复思路
5.本次恢复的数据库版本是10.2.0.4,根据mos描述,很多错误应不会发生,但是实际还是发生了,MOS的版本范围,不要太看重.
6.其实这篇文章的本质不是展示恢复过程,而是再一次提醒:操作数据库慎重,特别是一台机器上多套库.

library cache lock等待事件

Library cache lock介绍
Oracle利用Library cache lock和Library cache pin来实现并发控制,Library cache lock是在handle上获取的,而Library cache pin则是在data heap上获取。访问对象时,首先必须获取handle上的lock,然后将访问的数据pin在内存中。lock的作用是控制进程间的并发访问,而pin的作用是保证数据一致性,防止数据在访问时被交换出去。
lock和pin的实现类似于enqueue,在每个handle上都有lock和pin的holder list和waiter list,用来保存持有该资源和等待该资源的队列。

Library cache lock相关sql语句

--找出library cache lock等待sid,saddr信息
select sid,saddr from v$session where event= 'library cache lock';

SID        SADDR
---------- --------
16         572ed244

--找出blocked信息
select kgllkhdl Handle,kgllkreq Request, kglnaobj Object
from x$kgllk where kgllkses = '572ed244'
and kgllkreq > 0;

HANDLE   REQUEST   OBJECT
-------- ---------- ------------------
62d064dc          2 EMPLOYEES

--找出blocking信息
select kgllkses saddr,kgllkhdl handle,kgllkmod mod,kglnaobj object
from x$kgllk lock_a
where kgllkmod > 0
and exists (select lock_b.kgllkhdl from x$kgllk lock_b
where kgllkses = '572ed244' /* blocked session */
and lock_a.kgllkhdl = lock_b.kgllkhdl
and kgllkreq > 0);

SADDR     HANDLE   MOD         OBJECT
--------  -------- ---------- ------------
572eac94  62d064dc          3  EMPLOYEES

--blocking 会话信息
select sid,username,terminal,program from v$session where saddr = '572eac94'

SID        USERNAME     TERMINAL  PROGRAM
---------- -----------  --------- --------------------------------------------
12          SCOTT        pts/20    sqlplus@goblin.forgotten.realms (TNS V1-V3)

--所有blocked 会话
select sid,username,terminal,program from v$session
where saddr in 
(select kgllkses from x$kgllk lock_a 
 where kgllkreq > 0
 and exists (select lock_b.kgllkhdl from x$kgllk lock_b
             where kgllkses = '572eac94' /* blocking session */
             and lock_a.kgllkhdl = lock_b.kgllkhdl
             and kgllkreq = 0)
);

SID        USERNAME  TERMINAL  PROGRAM
---------- --------- --------- -------------------------------------------
13         SCOTT     pts/22    sqlplus@goblin.forgotten.realms (TNS V1-V3)
16         SCOTT     pts/7     sqlplus@goblin.forgotten.realms (TNS V1-V3)

library cache pin等待事件

library cache pin说明
library cache pin 事件是用来管理library cache的并发访问的, pin一个object会引起相应的heap被载入内存中,如果客户端需要修改或检测这个object它就必须在锁住后取得一个pin.library cache pin的等待时间为3秒钟,其中有1秒钟用于PMON后台进程,即在取得pin之前最多等待3秒钟,否则就超时.library cache pin通常是发生在编译或重新编译PL/SQL,VIEW,TYPES等object时.编译通常都是显性的,如安装应用程序,升级,安装补丁程序等,但object的重新编译也可能发生在object变得无效时.library cache pin的参数如下,有用的主要是P1和P2:
P1 – KGL Handle address.
P2 – Pin address
P3 – 10*Mode + Namespace
其中,P1,P2可与x$kglpn和x$kglob表相关.x$kglpn和x$kglob是ORACLE数据库的内部数据字典.
x$kglpn library cache pin信息
x$kglob library cache object信息

查询方法一

--通过查询V$SESSION_WAIT找出正在等待”library cache pin”的session
SELECT sid,
       SUBSTR (event, 1, 30),
       TO_CHAR(p1, 'xxxxxxxx') p1_16,
       --P1RAW P1_16,
       p2,
       p3
  FROM v$session_wait
 WHERE wait_time = 0 AND event LIKE 'library cache pin%';
--P1 列是Library Cache Handle Address
--P2 列是Library Cache Pin Address. 

--找到相关session pin状态
SELECT ADDR,
       INDX,
       KGLPNADR,-- Library Cache Pin Address
       KGLPNUSE,
       KGLPNSES,--识别锁住此pin 的session
       KGLPNHDL,--Library Cache Handle Address
       kGLPNLCK,
       KGLPNMOD,-- Pin 锁 
       KGLPNREQ-- Pin 请求
  FROM x$kglpn
 WHERE KGLPNHDL LIKE '%EB3EB8%';--p1_16
 
 --询X$KGLOB (Library Cache Object),可找到相关的object
SELECT KGLNAOBJ-- 相关object的名字(取前面80个字符)
  FROM X$KGLOB
 WHERE KGLHDADR LIKE '%EB3EB8%';--p1_16
 
 --查出占着pin锁的session目前正在做什么
SELECT a.sid, a.username, a.program
  FROM v$session a, x$kglpn b
 WHERE a.saddr = b.kglpnuse AND b.kglpnhdl LIKE '%EB3EB8%'--p1_16
  AND b.kgnmod <> 0;
  
   --查出阻塞者正执行的SQL语句
 SELECT sid, sql_text
  FROM v$session, v$sqlarea
 WHERE v$session.sql_address = v$sqlarea.address AND sid =&sid;

查询方法二

--通过查询DBA_LOCK_INTERNAL和V$SESSION_WAIT,可得到与”library cache pin” 等待相关的object的名字
SELECT TO_CHAR (SESSION_ID, '999') sid,
       SUBSTR (LOCK_TYPE, 1, 30) TYPE,
       SUBSTR (lock_id1, 1, 23) Object_Name,
       SUBSTR (mode_held, 1, 4) HELD,
       SUBSTR (mode_requested, 1, 4) REQ,
       lock_id2 Lock_addr
  FROM dba_lock_internal
 WHERE mode_requested <> 'None' AND mode_requested <> mode_held
       AND session_id IN
              (SELECT sid
                 FROM v$session_wait
                WHERE wait_time = 0 AND event LIKE 'library cache pin%');
                
 --查出”library cache pin”占有者(即阻塞者)的session id
 SELECT sid Holder,
       KGLPNUSE Sesion,
       KGLPNMOD Held,
       KGLPNREQ Req
  FROM sys.x$kglpn, v$session
 WHERE KGLPNHDL IN (SELECT p1raw
                      FROM v$session_wait
                     WHERE wait_time = 0 AND event LIKE 'library cache pin%')
       AND KGLPNMOD <> 0
       AND v$session.saddr = x$kglpn.kglpnuse;
       
 --查出”library cache pin”占有者(阻塞者)正在等什么
 SELECT sid, SUBSTR (event, 1, 30), wait_time
  FROM v$session_wait
 WHERE sid IN
          (SELECT sid
             FROM x$kglpn, v$session
            WHERE KGLPNHDL IN
                     (SELECT p1raw
                        FROM v$session_wait
                       WHERE wait_time = 0
                             AND event LIKE 'library cache pin%')
                  AND KGLPNMOD <> 0
                  AND v$session.saddr = x$kglpn.kglpnuse);
                  
 --查出阻塞者正执行的SQL语句
 SELECT sid, sql_text
  FROM v$session, v$sqlarea
 WHERE v$session.sql_address = v$sqlarea.address AND sid =&sid;