insert引起的死锁

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标题:insert引起的死锁

作者:惜分飞©版权所有[文章允许转载,但必须以链接方式注明源地址,否则追究法律责任.]

DEADLOCK DETECTED ( ORA-00060 )
[Transaction Deadlock]
The following deadlock is not an ORACLE error. It is a
deadlock due to user error in the design of an application
or from issuing incorrect ad-hoc SQL. The following
information may aid in determining the deadlock:
Deadlock graph:
———Blocker(s)——– ———Waiter(s)———
Resource Name process session holds waits process session holds waits
TX-000a0002-00005420 68 440 X 65 496 S
TX-0001001b-00002b19 65 496 X 68 440 S
session 440: DID 0001-0044-000A2346 session 496: DID 0001-0041-000CBA54
session 496: DID 0001-0041-000CBA54 session 440: DID 0001-0044-000A2346
Rows waited on:
Session 496: obj – rowid = 00014282 – AAAUKCAAMAAAEZrAAA
(dictionary objn – 82562, file – 12, block – 18027, slot – 0)
Session 440: no row
Information on the OTHER waiting sessions:
Session 496:
pid=65 serial=58006 audsid=1896040 user: 88/VAS
O/S info: user: web_meg, term: unknown, ospid: , machine: ezg-web1
program: JDBC Thin Client
application name: JDBC Thin Client, hash value=2546894660
Current SQL Statement:
insert into TAB_XN_CONTENT_TEMP (key,content) values (:1,:2)
End of information on OTHER waiting sessions.
Current SQL statement for this session:
insert into TAB_XN_CONTENT_TEMP (key,content) values (:1,:2)

我一看到这个错误,有点不明白,oracle 的insert操作竟然导致表被锁,然后查找些资料终于有了眉目:
当ORACLE执行insert等DML语句时,会首先自动在所要操作的表上申请一个TM锁,当TM锁获得后,再自动申请TX类型的锁。当两个或多个会话在表的同一条记录上执行DML语言时,第一个会话在记录上加锁,其它的会话处于等待状态,一直到第一个会话提交后TX锁释放,其它的会话才可以加锁。考虑是因为两个insert语句同时试图向一个表中插入PK或unique值相同的数据,而造成其中会话被阻塞,等待其它会话提交或回滚,因而造成死锁。这种情况,只要其中任何一个session提交,另外一个就会报出ORA-00001:违反唯一性约束条件,死锁终止;或者其中一个session回滚,另外一个即可正常执行。
通过对这段话的理解,应该是一个会话插入了一条记录未提交,然后另外一个会话继续插入主键或者唯一索引列相同的记录,导致死锁的发生。

环境模拟:
在会话1中执行下面语句
CREATE TABLE t1(ID NUMBER);
ALTER TABLE t1 ADD primary key (ID);
INSERT INTO t1 VALUES(1);
INSERT INTO t1 VALUES(2);

然后在会话2中执行下面语句
INSERT INTO t1 VALUES(1);
INSERT INTO t1 VALUES(2);

在会话3中查询死锁情况
通过上面模拟,重现了insert死锁现象,说明红色标注出来的文字的正确性

One thought on “insert引起的死锁

  1. INSERT INTO t1 VALUES(1);
    INSERT INTO t1 VALUES(2);
    然后在会话2中执行下面语句
    INSERT INTO t1 VALUES(1);
    INSERT INTO t1 VALUES(2);

    案例写反了,应当是在会话2执行:
    INSERT INTO t1 VALUES(2);
    INSERT INTO t1 VALUES(1);
    这样才能实现死锁,问题在对唯一值的持有上是独占的

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